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In this article, you will learn and get code to find and print largest of entered three numbers by user at run-time in C++. The program is created in following ways:

- Find largest of three numbers without function
- Find largest of three numbers using user-defined Function

Both program uses *if-else*, to find and print largest or biggest among any three numbers entered by user.

To find the largest number among three numbers in C++ programming, you have to ask
from user to enter the three numbers. Now use *if-else* ladder to find out the largest among three as shown in the
program given below:

The question is, **write a program in C++ that finds largest of three numbers.** Here is its answer:

#include<iostream> using namespace std; int main() { int numOne, numTwo, numThree, larg; cout<<"Enter the Three Numbers: "; cin>>numOne>>numTwo>>numThree; if(numOne>numTwo) { if(numTwo>numThree) larg = numOne; else { if(numThree>numOne) larg = numThree; else larg = numOne; } } else { if(numTwo>numThree) larg = numTwo; else larg = numThree; } cout<<"\nLargest Number = "<<larg; cout<<endl; return 0; }

This program was build and run under *Code::Blocks* IDE. Here is its sample run:

Now supply any three numbers as input say **1, 2, 3**. Here the third number is largest and second number
is second largest. Press `ENTER`

key to print the largest among these three numbers as shown in the
output given below:

Here is another sample run with user input **1, 3, 2**. Here the second number is largest and third number is
second largest:

Here is the one more sample run with user input, **3, 1, 2**:

The main logic behind the code is:

- Initially checks whether the first number is greater than second:
- If first number is greater than second, then checks whether second number
is greater than third:
- If it is true. Then first number is greater than second and second number is greater than third
- So the first number is the largest number

- And if second number is not greater than third, means that, the third number is greater than second
- Because third number is greater than second, so checks whether the third
number is also greater than first:
- If it is true. Then third number is greater than first and second both
- So the third number is the largest number
- And if third number is not greater than first, means that, the first number is greater than third
- Because first number is greater than third and second both
- So first number is the largest number

- If first number is greater than second, then checks whether second number
is greater than third:
- If first number does not greater than second, then second number is greater
than first:
- Because second number is greater than first, therefore checked whether
the second number is also greater than third:
- If it is true. Then second number is greater than first and third both
- So second number is the largest
- And if second number is not greater than third, means that, third number is greater than second
- Because third number is greater than second, and second number is greater than first
- So third number is the largest

- Because second number is greater than first, therefore checked whether
the second number is also greater than third:

The dry run of above program with user input **2, 1, 3** goes like:

- When user enters
**2, 1, 3**in same pattern, then 2 gets stored in**numOne**, 1 gets stored in**numTwo**, and 3 gets stored in**numThree**. That is,**numOne=2**,**numTwo=1**, and**numThree=3** - Now the condition,
**numOne>numTwo**or**2>1**evaluates to be true, threfore program flow goes inside the**if**block - Now the condition,
**numTwo>numThree**or**1>3**evaluates to be false, therefore program flow does not goes inside**if**'s body, rather it goes to its**else**'s part - And there, the condition
**numThree>numOne**or**3>2**evaluates to be true, therefore program flow goes inside the**if**'s body - And the value of
**numThree**gets initialized to**larg** - Because the condition evaluates to be true, therefore program flow skip
**else**'s part - And for outermost
**if-else**, because the condition of**if**evaluates to be true, therefore again in this case also,**else**'s part gets skipped - So program flow goes to the statement that prints the value of
**larg**as output - That will print the largest among entered three numbers

This program does the same job as of previous program. But internally this program uses a different approach
to do the task. That is, this program is created using a user defined function, **findLargest()**

The function, **findLargest()** takes three numbers as its arguments, and returns the largest among its
three argument. So the largest number gets returned by this function and initialized to **larg** inside the
**main()** function. Therefore just print the value of **larg**

#include<iostream> using namespace std; int findLargest(int, int, int); int main() { int numOne, numTwo, numThree, larg; cout<<"Enter the Three Numbers: "; cin>>numOne>>numTwo>>numThree; larg = findLargest(numOne, numTwo, numThree); cout<<"\nLargest Number = "<<larg; cout<<endl; return 0; } int findLargest(int nOne, int nTwo, int nThree) { if(nOne>nTwo) { if(nTwo>nThree) return nOne; else { if(nThree>nOne) return nThree; else return nOne; } } else { if(nTwo>nThree) return nTwo; else return nThree; } }

This program produces the same output as of previous program.

- C Find Largest of three Numbers
- Java Find Largest of three Numbers
- Python Find Largest of three Numbers

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